OMSH / INTERACTIVE NOTESSECTION 01 / 13
Worked example · 10 states

Probabilistic shielding

A robot must deliver a parcel through a busy warehouse. Follow the same MDP from computing its safety values to carrying a risk allowance along a run.

β*(s)The smallest achievable probability of ever reaching Collision from s.
β̄(s)A computed upper bound on β*. The shield uses this certificate.
(s, q)Physical state plus the allowance for future collision risk on this history. q is a scalar, not a Q-function.

There are eight decision states and two absorbing terminals. Collision is unsafe; Delivered is safe forever. The target is collision avoidance over an unbounded run, including any number of retries. A blocked route can keep you in the same state.

Warehouse routes

Click a state to inspect it. Faint arrows show possible safe-state routes. Coloured arrows show the selected action, labelled with its probabilities. β̄ is printed inside every state. Its collision arrow is red; absorbing terminal self-loops are omitted.

s₀ · Entry

Successor s′ P(s′ | s,a) β̄(s′) P × β̄

This sum is the risk of taking this action once, then using a certified backup. It is different from its immediate collision probability.

Every state and action: the full transition table
State Action Reward Successor probabilities Backup risk ρ

Original teaching MDP, with explicit chosen probabilities and action rewards. It is not a warehouse environment from either paper. All displayed values are computed from these rows. Reward is an immediate progress score and does not enter the safety solve.

Edwin’s paper · §3OmSh manuscript: ~/Projects/quartz/omsh-paper/main.tex, definitions augmented_sg, robust_floor_value, runtime_replacement.
Intuition · From winning regions

From certainty to a risk bound

A winning-region shield asks: “Can I stay safe for sure?” A probabilistic shield asks: “Can I keep the chance of ever becoming unsafe within this run’s allowance?”

State Where am I?Certificate β What risk does a backup need?Budget q How much risk may I allow?
TOY 01 · THE RIVER CROSSINGDrag to explore
A shortcut bridge and a safe detour The shortcut risks falling into an unsafe state. The detour reaches a safe terminal with no risk. Unsafe START SAFE EXIT SHORTCUT · REWARD 10 DETOUR · REWARD 2 · ZERO RISK
Safe terminalUnsafe terminalBoth routes end this toy episode.

Allow actions whose eventual risk fits q.

The winning region is still here.

At zero budget, an action must keep its entire probability support in states from which zero-risk continuation is possible. A bridge with even a tiny chance of falling fails that test. In deterministic dynamics, this recovers the familiar winning-region idea.

With q = 10%, an 8% bridge can be allowed. This toy has only one transition, so immediate and eventual failure coincide. In a longer game, they usually differ.

THE IDEA IN EDWIN’S PAPER

Remember the allowance.

Edwin Hamel-De le Court, Belardinelli and Goodall augment the state with a risk allowance. Their encoded action chooses an action distribution and successor allowances, constrained by an inductive safety certificate. Paper, §3 ↗

OmSh’s default uses pure actions and an automatic allocation. Its optional parameterized modes also learn successor allocations and two-action mixtures.

Key idea

A shield certifies a safe continuation, not just a harmless next move.

02 / A BUDGET BELONGS TO A HISTORY

Risk travels with
the branch you take.

Before acting, assign an allowance to every possible next state. Keep their probability-weighted average within today’s budget. After the transition, carry the allowance of the state you actually reached.

FEASIBILITYW(s′) ≥ β(s′)Enough for a safe continuation.
ACCOUNTINGΣ P(s′) W(s′) ≤ qTomorrow’s average fits today.
UPDATEqnext = W(realized s′)Carry one branch’s allowance.
TOY 02 · ONE DECISION, TWO POSSIBLE FUTURESq = 20%
Today20%risk allowance
80% of outcomes20% of outcomes
A · COMMON ROUTE10%next allowanceMinimum βA = 5%
B · RARE ROUTE60%next allowanceMinimum βB = 10%

Choose a realized successor to see the update:

Choose A or B above.

How can 20% turn into 60%?

Because the 60% allowance applies only after a branch reached with probability 20%. With A at 10% and B at 60%, the weighted allowance is 0.8 × 0.10 + 0.2 × 0.60 = 0.20.

This bounds failure from the original state by 20%, even if failure conditional on B can be as high as 60%. The budget can rise along a realized path; it is constrained in expectation.

β is a floor; q is an allowance.

The certificate β says how much eventual risk a safe backup may need. Assigning B a zero budget would leave no feasible continuation when its best available action still has 10% risk.

The default fill starts at β and raises all unsaturated allowances by the same amount until a constraint binds. Here it gives A = 19% and B = 24%. “Egalitarian” refers to equal increments.

WHY A FIXED PER-STEP THRESHOLD FAILS

“Just allow 10% every time” adds up.

Take a fresh 10% failure gamble each step. Each decision passes a naïve 10% check, but the chance of at least one failure grows.

With a global 10% budget and a first gamble that already has 10% immediate failure, the unsafe branch gets W = 1. The surviving branch must get W = 0, since 0.10 × 1 + 0.90 × W ≤ 0.10. You cannot take a second 10% gamble there.

Why this proves eventual safety

Unsafe successors have certificate and allowance 1. Safe successors inherit a certified allowance. If their future failure chances stay below those allowances, the law of total probability bounds today’s failure chance by the weighted allowance, hence by q. Repeat this argument for any finite number of steps, then take the limit. Robust OmSh enforces the same inequality for every retained opponent level, using one shared W vector.

TAKE THIS WITH YOU

The next budget is selected by the outcome. It is not “q minus the action’s risk.”

03 / COMPUTE THE BACKUP BEFORE LEARNING REWARD

Two bounds.
One dependable certificate.

Value iteration propagates risk backward through the graph. The repo tracks a lower and an upper bound on the minimum eventual failure probability. The shield uses the upper bound.

TOY 03 · THE WAITING ROOMInfinite horizon
92%Return to this roomTry again next step ↻
6%Reach a safe exitTerminal value 0
2%Become unsafeTerminal value 1
Upper: used by shieldLower: diagnosticExact toy value
Lower
Upper

Each pass: new bound = 0.02 + 0.92 × old bound. The safe-exit contribution is 0.06 × 0.

2% next step. 25% eventually.

You may revisit the room many times. Solve V = 0.02 + 0.92 V to get V = 0.25. A small immediate hazard can hide a large eventual risk.

Start with L = 0 and U = 1. L rises and U falls. Their gap measures remaining uncertainty about the solution. Small changes in L alone do not certify a small error.

“Sound” means the bound is safe to use.

An upper bound may block an action before enough iterations have tightened it. That is conservative: it avoids admitting an action using an optimistic estimate.

An inductive certificate also satisfies Bellman(β) ≤ β. That means every state has a backup action whose expected successor certificate fits its own certificate. This gives the budget a feasible continuation.

THE FIXED-POINT TRAP

A safe self-loop can fool the upper iteration.

If a room loops to itself safely with probability 1, its true minimum failure probability is zero. But starting at U = 1 gives Unext = U forever.

U = 100%

A small residual (zero!) did not find the right value.

The repo first finds the largest safe set with an action that keeps all supported outcomes inside it and has no missing mass. Those states are fixed to zero. Unsafe states are fixed to one. Unaccounted probability goes to an explicit unsafe sink, rather than being renormalized away.

How this relates to “Sound Value Iteration” in the paper

The paper permits several algorithms producing an inductive upper certificate, including Sound Value Iteration. The repo’s function named sound_value_iteration_min_reach_upper uses monotone lower/upper interval updates, an almost-sure safe-set anchor, and outward numerical padding. This toy illustrates that implementation’s nominal interval logic; it does not reproduce every step of the published Quatmann–Katoen algorithm.

With optional transition ambiguity sets, the lower and upper operators can have different fixed points. Their gap can then express model uncertainty as well as numerical error, so it need not close to zero.

TAKE THIS WITH YOU

VI computes a backup risk certificate. PPO later learns reward-seeking behaviour inside its constraints.

04 / LEARN WHERE THE ALLOWANCE IS USEFUL

The limit is chosen.
The allocation can be learned.

The learner cannot vote to ignore max_risk. It can discover that extra allowance is more valuable in one future state than another, and propose a better allocation.

YOU CHOOSE

Initial q

The experiment’s safety target. Raising it changes the contract.

VI COMPUTES

Certificate β

A conservative backup demand, computed from the WM/OM graph.

PPO CAN LEARN

Successor W

How to distribute allowance to improve future return.

TOY 04 · A USEFUL BUDGET PROPOSALSafe radial projection
ProposedProjectedMinimum β

A finite grid search illustrates the objective. This website does not train PPO.

Propose a direction. Shrink it safely.

The raw Gaussian action gives logits z. Convert each to a proposed allowance between β and 1 using a sigmoid. If the proposal overspends, shrink all its extra allowances by the same factor λ until every active level’s constraint holds.

This preserves the learner’s allocation direction. It is a radial projection from β, rather than the nearest point in Euclidean distance.

The reward arrives later.

Higher WB can unlock B’s high-reward action. If B is reached, the policy observes that budget and uses the opportunity. PPO connects the later return to the earlier proposal.

PPO stores and scores the raw augmented action. The shield’s sigmoid, projections and primitive-action sampling are environment dynamics. Learning does not need to backpropagate through the shield.

See the projection calculation
W̃ = β + (1 − β) sigmoid(z)
d = W̃ − β
λ = clip[0,1] min(1, minℓ (q − Pℓ·β) / (Pℓ·d))
W = β + λd

Skip zero denominators. An infeasible β means the state’s backup needs more risk than q: raise an infeasibility error. Numerical projection failures fall back to β. Safety is a hard constraint; a high reward never compensates for overspending.

Two choices, four implemented variants.

Variant Primitive action Successor allocation Config value
Egalitarian Pure DEFAULT One action Automatic equal increments pure
Egalitarian Mixed Learned two-action mixture Automatic equal increments egalitarian_mixed
LearnedBudget Pure One action Learned, then projected learned_budget_pure
LearnedBudget Mixed Learned two-action mixture Learned, then projected learned_budget_mixed
BONUS · MIXTURE SAFETY IS IN EXPECTATION

Two blocked endpoints can have a safe mixture.

For actions A and B, L0 gives risks (10%,50%) and L1 gives (50%,10%). At q = 32%, neither pure endpoint is safe against both levels. An intermediate mixture can be.

v(x) = (1 − x) A + x B

Both level constraints must hold. Sampling B need not be individually admissible as a pure action at q. A third backup action has 25% risk under both levels.

The combined variant first projects the action mixture using β, then projects W using that mixture’s successor probabilities. Pairwise mixtures do not represent every possible distribution over three or more actions. PPO may also find a poor allocation; projection guarantees feasibility, not optimal learning.

TAKE THIS WITH YOU

“Learn the budget” means learn its allocation while the shield enforces the chosen limit.

05 / WHICH OPPONENTS MUST THIS ACTION TOLERATE?

Beliefs can move.
The floor only rises.

Opponent levels are imagined policies, not danger scores. The posterior measures which level explains observed behaviour. The floor says which lower-level hypotheses the shield has permanently removed.

ACTUAL OPPONENT

What happens

The opponent’s behaviour may change. An inferred level does not make the real opponent change.

POSTERIOR α

What we believe

Soft weights over L0, L1, L2. These can move up or down after observations.

FLOOR f

What we retain

At f = 1, safety is robust over L1 and L2. L0 has been excluded.

TOY 05 · WATCH THE GATE, NOT JUST THE ARGMAX
Candidate estimate
Evidence streak
Committed floor
Action L0 L1 L2 Used risk Admissible?

Toy risks are eventual terminal-failure probabilities. “Wait” gets more dangerous at higher levels; “Shortcut” gets less dangerous.

INJECT ONE NEW POSTERIOR

Each button stands for one successful opponent-model update. These weights are illustrative inputs, not a fitted Bayesian model.

Changing mode or patience starts a new toy instance. Episode reset preserves posterior, floor, streak and observation count.

Observation history
Update Posterior (L0 / L1 / L2) Estimate Streak Floor
What does another opponent reasoning level mean?

L0 copies opponent behaviour from pre-training. To imagine L1, first train a focal response to L0, then an opponent best response to that focal policy. Repeat the alternating responses to build L2. Intuitively: “I adapt to you adapting to me.” These are offline imagined policies, not three observed stages the real opponent is guaranteed to pass through.

The online OM asks which of those policies best explains each observed opponent action. Its Bayes-style likelihood update is temperature-smoothed and averaged over time. That belief update is separate from the shield’s patience gate. None of these steps implies that higher levels are more dangerous: compare Shortcut and Wait in the toy table.

MAP + patience is a heuristic.

The default uses the most likely level (MAP) as the estimate. A 40% lead can request a raise even with 60% belief elsewhere. Patience counts consecutive successful updates supporting the next raise; contradictory evidence resets that streak.

With patience 3, a jump in the estimate to L2 takes three supporting updates to reach floor 1, then another three to reach floor 2. With patience 0, the implementation jumps directly to the estimated level. Calling inspection repeatedly does not count as new evidence.

Credible floor asks a stronger question.

Choose the largest suffix whose posterior mass is at least 1 − δt, then apply the same patience gate. A weak L2 lead usually leaves L0 in the set.

The floor remains irreversible even if the posterior later reverses. The repo logs excluded mass and a tail-constraint miss; it does not lower the floor or repair the assumption automatically.

Mode Safety aggregation What the claim needs
monotone_floor Worst case over ℓ ≥ f True active level remains in that suffix; patience alone does not prove this.
credible_floor Worst case over a credible suffix Calibrated posterior coverage, monotone true levels, correct/covered dynamics.
all_levels Worst case over every level forever True transitions remain in the compiled level family, even when levels switch downward.
bayesian_mixture Posterior-weighted transition A model-relative mixture interpretation; no worst-case level-switching claim.
WHY THERE ARE TWO CREDIBLE SCHEDULES

5% each time is not 5% ever.

The summable schedule spends δt = 6δ / [π²(t+1)²]. All its allowances together sum to δ. A union bound can then control “ever excluded the true level,” under the stated calibration and monotonicity assumptions.

These are union-bound allowances, not measured exclusion rates.

For credible-floor notebook runs, a total target of 20% with a 5% tail allowance initializes the model-controlled budget at 15%. With the summable schedule and the required assumptions, the nominal total is 15% + 5% = 20%. Direct wrapper construction takes the model component as init_safety_bound. A fixed schedule does not give this anytime tail guarantee. Credible-floor is retained as a diagnostic/ablation; the current primary comparison uses monotone-floor.

Why raising the floor keeps the carried budget feasible

The robust certificate solves a minimum over actions, followed by a maximum over retained levels. Removing levels weakens that maximum, so the required backup risk cannot increase. A successor budget assigned under the old floor still covers the next state after a raise. The floor change itself does not alter q.

Bayesian-mixture mode keeps an all-level robust continuation certificate but uses the current posterior mixture for the one-step action and allocation constraint. This preserves a feasible backup after posterior changes; it does not establish a full belief-state infinite-horizon theorem.

TAKE THIS WITH YOU

Higher levels are different policies. A higher floor removes hypotheses; it does not make the world inherently safer.

06 / FOLLOW ONE ACTION THROUGH OMSH

One safety contract.
Several moving parts.

World modelling gives the transition probabilities. Opponent modelling gives the level-specific policies. The shield combines them, computes a backup certificate, and carries a budget while the reward policy learns.

01 · BUILD

World + opponent

Pℓ(s′ | s,a) =
Σopponent actions Γ(s′ | s,a,a−i) π̃ℓ(a−i | s)

One induced focal MDP per level.
02 · CERTIFY

Robust floor values

mina maxℓ ≥ f Eℓ[β̄f(s′)]
≤ β̄f(s)

Inductive upper certificate. Unsafe = 1; safe invariant set = 0.
03 · RUN

Action + allocation

Check against q.
Project W.
Carry W(realized s′).

Then update the OM and floor.

The runtime, step by step.

  1. Observe the augmented state. The focal learner sees the base observation plus current budget and floor. Mixture mode also exposes the posterior.
  2. Build the admissible set. For each pure action, compute maxℓ ≥ f Pℓ,a·βf. Compare it with q. A masked PPO actor samples from admissible actions.
  3. Handle an unsafe external proposal. Keep a feasible proposal; otherwise choose the highest predicted reward among feasible replacements. The default reward ranking is posterior expected reward; minimum reward is an ablation.
  4. Allocate successor allowances. Start at the robust floor certificate. Use egalitarian fill or project a learned proposal. One W must satisfy every active level’s expectation constraint.
  5. Execute and carry. Set q to the allowance of the observed successor. Update the opponent posterior using its observed action and the pre-step public state, then apply the floor gate.
Why “maximum of per-level minima” is not the robust certificate

Suppose A has risk 0 under L0 and 1 under L1, while B has risk 1 under L0 and 0 under L1. Each level separately has minimum risk 0, but no single pure action achieves that across both levels. The robust pure-action value is mina maxℓ risk = 1, whereas maxℓ mina risk = 0.

The repo therefore computes a separate robust floor-wise continuation certificate rather than taking the maximum of independently solved level values. Optional mixed variants also retain this conservative pure-action certificate as a lower limit on successor allowances. They can improve current-step choices without solving an optimal mixed-action continuation program.

What kind of safety is being bounded?

The default graph is time-free and targets eventual unsafe reachability. A hidden simulator step limit does not silently turn this into a finite-horizon certificate.

Reset starts a new episode’s risk query and restores its initial budget. A per-episode 10% bound does not mean at most a 10% chance of ever failing across infinitely many episodes.

What does the certificate depend on?

A sound solve certifies the supplied model. Real-world safety additionally depends on dynamics accuracy, graph support and coverage, unsafe labels, and the actual opponent staying within the retained assumptions.

Missing mass is treated as unsafe. This handles explicit graph deficits; it does not automatically bound all errors in learned probabilities.

Three different baselines and guarantees in this repo

Learned OmSh: freezes a bundle induced from learned world/opponent models. Its certificate is relative to those kernels unless further error guarantees apply.

True-policy shield: uses exact dynamics and the current live opponent policies, periodically rebuilding the bundle. Exact policy access is an evaluation baseline, not a guarantee against arbitrary opponent actions.

Exact anytime adversarial audit: preserves each joint-opponent-action row and takes its worst case. An independently checked certificate can bound one focal agent’s per-episode risk against arbitrary opponent actions on the declared exact graph and reset support. It may be infeasible at the chosen target; it is separate from the default learned floor heuristic.

Optional count-based ambiguity sets and padded transition constraints address probability uncertainty under their own support, confidence and coverage assumptions. They do not learn the initial risk target. See the source notes below for the theorem-facing details.

A small vocabulary to keep straight.

Symbol / setting Meaning here What changes it?
max_risk Chosen initial episode target Experiment configuration
q / current_safety_bound Current conditional risk allowance Realized successor’s W, or episode reset
βf Robust backup certificate for floor f Offline bundle build / selected floor
W(s′) Allowance assigned to a possible successor Egalitarian fill or projected learned proposal
α / mix_alpha Opponent-level posterior weights Observed opponent actions and OM update
f / level_floor Lowest retained opponent level Configured estimate rule and patience gate
δtail Allowance for credible-level exclusion Configuration and schedule, not PPO
ONE LAST CHECK

After a rare branch, q rises from 20% to 60%. Is the shield broken?

Sources & code trail.

Checked against the local repo and ~/Projects/quartz/omsh-paper on 2 October 2026. Every numerical demo is a toy, not an experiment result.

TAKE THIS WITH YOU

PPO learns actions and allocations; the shield checks their continuation-risk constraints.

Further theory · 1 of 2

From an opponent model to a shield

The world model predicts what happens after joint actions. The opponent model predicts which actions the other agents take. Together they give the transition rows used by the shield.

1. Build imagined opponent policies

Level 0 clones observed opponent behaviour. To construct level m + 1, improve a focal policy against opponent level m, then improve the opponent against that focal policy using imagined rollouts. This is an alternating best-response construction, not a measurement of an opponent’s intelligence.

OmSh manuscript · Recursive Imagined Opponent Policies; eq:soft_q_rollout and eq:soft_pi_target_nolegal
Q̂−im(s,a−i) = EΓ, πim, π̃−im[ ∑h=0H−1 γh r−it+h | st=s, a−it=a−i ]
π̃−im+1,tgt(a−i | s) = exp(Q̂−im(s,a−i)/τ) / ∑b exp(Q̂−im(s,b)/τ)

Fit the next policy to this soft target. The rollout horizon H helps build the opponent hypothesis; the shield’s unsafe-reachability objective remains infinite-horizon. The method needs observed or derivable opponent rewards.

2. Update the belief using observed actions

OmSh manuscript · Bayesian Mixing
bℓ = αℓ,t−1 π̃−iℓ(a−it | st) / ∑k αk,t−1 π̃−ik(a−it | st)
αℓ,t = (1 − η) αℓ,t−1 + η softmax(log b / T)ℓ

Exact Bayes is T = 1, η = 1. The implementation can temper and smooth the update. These α values are beliefs over levels; Edwin’s allocation α is the W used elsewhere on this site.

Use the warehouse’s two hypotheses: level 0 yields with probability 0.2, level 1 with probability 0.8. Begin with equal prior weight, then observe yield or push.

1.01.00
Observation Prior α₀ / α₁ Exact Bayes b₀ / b₁ Tempered, smoothed α₀ / α₁

This demonstration applies the stated Bayes/temperature/EMA equations to fixed hypotheses. It does not train opponent networks or advance a floor. Raising the floor is a separate irreversible decision, illustrated in Levels & floors.

3. Compile a kernel for each level, then certify

OmSh manuscript · def:induced_safety_game and def:robust_floor_value
P′ℓ(s′ | s,ai) = ∑a−i Γ(s′ | s,ai,a−i) π̃−iℓ(a−i | s)
β*f(s) = mina maxℓ ≥ f P′ℓ,s,a · β*f,   s ∉ U

The posterior can rank already-safe actions by expected reward. Robust safety still checks every retained level, using one common W. A high posterior weight does not turn a model prediction into a coverage guarantee. Higher levels also need not be safer; the warehouse’s more cooperative higher level is a chosen example.

Source: ~/Projects/quartz/omsh-paper/main.tex, sections Multi-agent Model-Based Opponent Modelling and Probabilistic Shielding.Belief update implementationImagined-level construction
Further theory · 2 of 2

What the safety theorem needs

A valid certificate gives a bound for the dynamics it covers. Your manuscript explains how to lift that statement to the real game, including model uncertainty and opponents that change over time.

The equations below show the pure-action special case. The updated manuscript also permits a distribution over action–allocation pairs and outer sets of whole action-row families: see Randomisation & timing. Count-based coverage makes the statistical set concrete; Risk dominance gives a weaker sufficient condition.

One-step certificates imply a whole-run bound

OmSh manuscript · def:anytime_runtime_certificate and thm:anytime_safety
Wt(s′) = 1 for s′ ∈ U,   supP ∈ 𝔓t(ht,at) EP[Wt(s′)] ≤ qt
qt+1 = Wt(st+1),   q₀ = p
Pr( ∀t: Ptruet ∈ 𝔓t ) ≥ 1 − δcov   ⇒   Pr(ever U) ≤ min(1, p + δcov)

The set and allocation must be chosen before seeing the next outcome, with a feasible certificate at every safe history. The theorem starts at a safe initial state and does not cover an uncertified pre-training prefix.

Before a collision or the first coverage failure, the average next allowance is at most the current one. In probability language, this is a nonnegative supermartingale. Freeze it at either event: entering Collision forces q = 1, so the probability of a covered collision is at most the initial p. Coverage can fail with probability at most δcov; add that once. Conditioning directly on “coverage holds forever” could change transition probabilities, so the manuscript uses this stopped-process argument.

These bounds concern one focal agent and one run carrying its budget. Restoring q = p at reset starts a new per-episode query; it does not create a single lifetime bound across repeated resets.

Opponent switching and floor changes

Checking all retained rows also checks their convex combinations. This tolerates arbitrary switching among covered levels. Raising the floor reduces the checked set and can loosen β̄, provided the computed certificate family is ordered accordingly. It leaves the carried q unchanged. Safety under this coverage theorem still requires the true row to remain covered: a MAP estimate alone does not establish that, and an irreversible floor can exclude a model that later fits the opponent again. Failure of coverage alone does not prove a safety failure; the updated risk-dominance corollary examines the committed W directly.

Three different kinds of error

Quantity What it means Where it enters
εVI Error in the computed β̄ relative to β*. Conservatism of the safety certificate; not an extra failure probability when β̄ is valid.
r = εWM + εOM TV-distance radius around induced level kernels. The robust next-state set. A radius needs a valid coverage argument.
δcov, optionally δtail Probability that the coverage contract fails, or a separately justified credible-floor exclusion fails. Reserve these from the end-to-end risk target; avoid counting the same event twice.

A small persistent point-model error is insufficient for infinite-horizon safety. If a model says “safe self-loop” but the real process has an unmodelled collision probability ε on every visit, its risk after H visits is 1 − (1 − ε)H, tending to 1. The true law needs to lie in the set the shield actually checks.

Reserve the error budget before starting

Assume the displayed error probabilities have been justified. For a separately accounted credible-floor tail, use p = ptotal − δcov − δtail. If δcov already covers all floor exclusions, set the additional tail reserve to zero. A summable tail schedule is conditional on the stated calibration and level assumptions.

25%3%2%

The feasibility comparison uses the warehouse’s floor-0 certificate, β̄(Entry) ≈ 17.68%. These sliders illustrate accounting; they do not certify model coverage. Enlarging a real ambiguity set also requires recomputing its backup demand.

Safety and optimality are separate claims

Edwin’s full construction includes the feasible action-distribution polytope’s vertices and arbitrary valid successor allocations. With the exact safety value it recovers the optimal safe reward under the paper’s assumptions; the approximation-limit result uses strict feasibility (Slater’s condition). Our pure-action trajectories and restricted allocation search preserve the safety inequalities but can remove reward-optimal choices. PPO itself is not guaranteed to find a global optimum. OmSh adds conservatism over opponent levels and model uncertainty.

Your updated robust permissiveness theorem states a path-law approximation bound for the full randomised shield at a fixed level set. It separates the mixed robust value from the pure certificate and does not claim that the implemented PPO controller finds the existential policy.

Reading the tutorial slides alongside the paper

The slides use βt for the carried budget, corresponding to qt here; their β* is the minimal risk, and α is the successor allocation W. Their δ for VI termination is an accuracy tolerance, not δcov.

Printed slides 103 and 109 put βt+1 on the right of the expected-allocation inequality. Under the stated state/action timing, this appears to be an indexing typo: Edwin’s Definition 3 compares the allocation to the current budget qt, then sets qt+1 from the realised successor. This website follows Definition 3.

Edwin · Definitions 2–3, Theorems 1–2AAMAS tutorial · printed slides 103–113OmSh manuscript: as:anytime_coverage, def:anytime_runtime_certificate, thm:anytime_safety, cor:padded_omsh and their appendix proofs.
Updated theory · 1 of 4 · Manuscript checked 5 October 2026

Why the order of choices matters

Your paper now distinguishes the pure-action runtime wrapper from a more permissive randomised shield. The key question: can the opponent see your sampled action before choosing its level?

Simultaneous moves put the maximum outside the mixture

The opponent may use the entire past to pick today’s level. It picks before the focal controller draws today’s action and allocation. It knows the distribution, but cannot react to the draw.

  1. From the current history, choose a distribution ν over pairs (a, W).
  2. The opponent’s active level is fixed for this step; sample (a, W) from ν.
  3. Draw s′ from that level’s row for a, then carry q′ = W(s′).
OmSh · def:fixed_floor_shield; def:anytime_runtime_certificate
ρΛ(s,ν) = maxℓ ∈ Λ E(a,W) ∼ ν[ ∑s′ P′ℓ(s′ | s,a) W(s′) ] ≤ q

For a general outer family set, replace max over levels with sup over F ∈ 𝔉, and P′ℓ(· | s,a) with Fa. One F describes the rows across all sampled actions together.

A crossing with two conflicting hypotheses

For this calculation, a crossing ends in Delivered or Collision; W is 0 or 1 respectively, so the table entries are both collision probabilities and expected successor allowances. The ten-state warehouse remains the multi-step example.

Chosen level Action A Action B
L0 0% 40%
L1 40% 0%

Let x be the probability of B. A single level produces risk 40%x or 40%(1 − x). With x = ½, both give 20%, even though each pure action’s worst case is 40%.

50%20%
Level held for the draw Mixture’s E[W] Budget check

If the opponent could react after seeing A or B, it could always pick the dangerous level. Then E[maxℓ cost] is 40%, whereas maxℓ E[cost] is 20% at the balanced mixture. Neither calculation averages levels using posterior weights.

Actions and their allocations may be correlated

At q = 20%, this crossing can use its exact mixed certificate: β(Entry) = 20%, β(Delivered) = 0 and β(Collision) = 1. Keeping the 40% pure certificate would fail the theorem’s initial β(s₀) ≤ p premise at that budget. The next page explains this certificate gap.

OmSh · def:fixed_floor_shield
𝒦Λβ(s,q) = { ν : W ≥ β for ν-almost every pair, ρΛ(s,ν) ≤ q }

β is an inductive certificate with β = 1 on unsafe states; hence every sampled W also equals 1 there.

The draw can choose A with WA, or B with WB. An individual pair need not fit q by itself: the distribution must fit every level’s expectation. After the draw, use that pair’s W. Replacing this constraint with a check of every sampled pair would discard safe mixtures.

The existing pairwise learner uses a common W and a selected action edge; the pure runtime wrapper uses a point mass on one (a,W). Both are restricted constructions. The theorem describes the larger set, rather than claiming those implementations explore all of it.

How many pairs do we need?

For finitely supported ν, the paper’s “Few atoms suffice” proposition decomposes it into feasible mixtures, each using at most |Λ| + 1 pairs from its support. Three retained levels mean at most four pairs per component. Preserving an arbitrary original path law may require randomising over those components; the proposition does not compress every distribution into one four-pair distribution.

Source: omsh-paper/main.tex, def:fixed_floor_shield, thm:fixed_floor_permissive, prop:two_atoms. The timing is part of the mathematical model, not a switch to change the opponent’s information in the deployed game.

Updated theory · 2 of 4

Safe, and how much does it exclude?

Soundness says every admitted controller is safe. Permissiveness asks whether safe policies can still be represented. Your updated theorem quantifies that second question.

There are now two robust safety values

OmSh · def:robust_floor_value; def:fixed_floor_shield
β*Λ: least fixed point of mina maxℓ ∈ Λ P′ℓ,s,a · v
βmixΛ: least fixed point of minσ ∈ Δ(A) maxℓ ∈ Λ ∑a σ(a) P′ℓ,s,a · v
βmixΛ ≤ β*Λ,   βmixΛ ≤ β

Both operators fix unsafe states to 1; the displayed minimisations apply at safe states. Here β is an inductive certificate, with β = 1 on unsafe states and TmixΛβ ≤ β. A pure-action upper certificate is also valid for the mixed operator and additionally lies above β*Λ. It may be conservative even if its pure-action solve is exact. In the previous page’s crossing, the pure value is 40% and the mixed value is 20%.

The gap and the available slack

OmSh · thm:fixed_floor_permissive (ii)
d = ‖β − βmixΛ‖∞,   slack = p − β(s₀)
ε = 0 if d = 0; otherwise ε = d / (d + p − β(s₀)), requiring β(s₀) < p
TV(path law of compliant controller, path law of π) ≤ ε
| Econtroller[G] − Eπ[G] | ≤ 2Bε,   |G| ≤ B

Fix a nonempty level set Λ and any history-dependent policy π that is p-safe against every allowed level sequence. There exists a compliant, potentially history-dependent controller with this approximation guarantee under every sequence. It is an existence theorem; it does not say PPO finds that controller.

Intuitively, inflate π’s continuation allowances to clear the upper certificate, then put a little probability on an inductively safe backup. The backup compensates for the inflated initial expectation. More initial slack means less backup mixing is needed.

2.0%25.0%

This calculator assumes a valid β with β(s₀) = 15% and the supplied global gap d. It does not construct such a certificate. d is an absolute probability difference, not a percentage of β. For discounted rewards bounded by |r| ≤ R and γ < 1, one can take B = R/(1 − γ).

What this result does and does not recover

A bound you can compute without the exact mixed value

Start mixed Bellman iteration from 1U to obtain a lower iterate βk. Then βk ≤ βmixΛ ≤ β and d ≤ ‖β − βk‖∞. Substituting that upper bound for d gives a conservative ε bound. Each mixed update solves a small matrix game; the website’s original warehouse solver still uses the pure operator.

Current manuscript example: Pursuit–Evasion, floor 0
Using d ≤ 0.0145 and initial slack 0.0085 gives ε ≤ 0.0145/(0.0145 + 0.0085) ≈ 0.63. A small value gap can yield a loose permissiveness bound when slack is small. This is a model-level bound, not an observed 63% reward loss.

Source: omsh-paper/main.tex, thm:fixed_floor_permissive and its proof; campaign values checked at revision e049b7c. Original-game reward optimality still depends on whether the level model excludes policies that the real opponents make safe.

Updated theory · 3 of 4

Which model carries the coverage claim?

The learned world model is useful for imagination and reward prediction. The paper’s concrete statistical certificate is centred on observed transition counts. They have different jobs.

Counts define a time-uniform outer set

Fix one state–joint-action row with m legal successors. After n visits, P̂n is its empirical distribution. Choose a total coverage-failure budget δcov, divide it across the finite set of R rows, and spend each row’s allowance across all visit counts.

OmSh · prop:tv_confidence_sequence; cor:row_union_bound
δrow = δcov/R,   δn = 6δrow/(π²n²),   n ≥ 1
rn = min{1, ½√[ 2(m ln 2 + ln(π²n²/(6δrow)))/n ]},   m > 1, n ≥ 1
𝒢n = { P on the legal support : TV(P,P̂n) ≤ rn }

For m > 1, use a uniform centre and radius 1 at n = 0. For m = 1, the radius is 0 even without visits, because a correct singleton support already determines the row. Adaptive visit times are allowed under stationary, state-sufficient dynamics with fresh transition randomness. Changes in the environment’s transition law would require another argument.

δcov is chosen by the designer, not learned from held-out accuracy. The data determine the centre and radius. The statement is simultaneous over all counts and all rows, so it pays miscoverage once.

What a TV ball does to a committed W

Here one legal row has three successors and W = (5%, 30%, 100%). For positive n, counts keep the proportions (60%, 35%, 5%) to isolate the effect of sample size. Increasing n here is a comparison of count tables, not simulated new observations. Marked route and Inspection retain those continuation allowances; Collision has W = 1.

5%
20%40%

Legal successor Committed W Empirical P̂ Worst-case P
OmSh · lem:tv_ball_bellman
supTV(P,P̂) ≤ r EP[W] ≤ min{1, EP̂[W] + r(Wmax − Wmin)}

The exact supremum moves up to r probability mass from low-W successors to high-W successors. Donors can run out and recipients can fill up, so the displayed cheap bound is an inequality.

A different centre needs a different radius

A count-derived radius cannot simply be placed around the learned Γ. By the triangle inequality, radius min{1, rn + TV(P̂n,Γ)} around Γ contains the count ball and retains its coverage, but may be wider. The paper keeps the count-centred set as the certified object.

Joint-action row coverage must then be combined with an opponent-action envelope. Taking all opponent distributions covers arbitrary adaptive behaviour; a narrower envelope needs its own validity argument. Complete legal support and correct unsafe labels remain necessary. An ambiguity ball redistributes legal mass; it does not invent an unsafe successor that the dynamics rule out.

Freeze the sets, then run episodes

After a data-collection prefix, freeze these sets. With probability at least 1 − δcov over that prefix, every later compliant episode is p-safe, conditional on the prefix, provided the opponent envelope always covers its behaviour. This is a two-stage statement, not a bound on ever failing across infinitely many episodes. The uncertified collection prefix is outside it.

For the unconditional one-run target ptot, the earlier accounting still uses p = ptot − δcov. Neither count-based coverage nor padded level sets remove the need for a feasible runtime certificate at every safe history.

Source: omsh-paper/main.tex, prop:tv_confidence_sequence, cor:row_union_bound, lem:tv_ball_bellman, cor:frozen_sets. This row calculator is ordinary floating-point teaching code, not a certified whole-game solver.

Updated theory · 4 of 4

Wrong about the opponent, still safe?

For the pure runtime wrapper, coverage contains the true law in a certified set. Risk dominance asks something weaker: under the W actually committed, does the true expectation still fit the carried q?

OmSh · cor:risk_dominance
ηt = ( EPtruet(· | ht,at)[Wt] − qt )+
Pr(τU ≤ T) ≤ p + E[ ∑t < T ∧ τU ηt ]
ηt = 0 almost surely for every safe step ⇒ Pr(ever U) ≤ p

W is chosen before the next outcome, stays in [0,1], and equals 1 on unsafe successors; q′ = W(s′). The excess-corrected stopped budget is a supermartingale. An outside-set opponent can have zero excess if it avoids transitions with large W.

This corollary measures excess after (a,W) is drawn. A general randomised shield can be safe in expectation over ν even when some sampled pairs have positive excess. Thus zero excess for each realised pair is not required by the randomised soundness theorem. Here we analyse the pure per-step wrapper and its committed W.

A repeatable inspection row

Collapse a warehouse run to Entry, Inspection, Delivered and Collision. Entry and Inspection use the same row; Inspection can repeat, and the other two destinations are absorbing. Start at Entry with p = 30%. Commit W(Delivered) = 0, W(Inspection) = 40%, W(Collision) = 100%. Entering Inspection therefore carries q = 40%; it does not refill to 30%.

The certified row centre is (50%, 40%, 10%), with TV radius 2% on these three legal successors. Its worst expected W is 28%, fitting both Entry’s 30% and Inspection’s 40%. Below, choose the true row and compare coverage with excess.

10%5%20
Successor True probability Carried W
How this finite-horizon calculation works

Write w for Inspection probability and c for Collision probability. Collision by T has probability c∑t=0T−1wt. Entry’s excess is (c + 0.4w − 0.3)+; Inspection’s is (c + 0.4w − 0.4)+. The expected stopped excess sum is ηEntry + ηInspection∑t=1T−1wt. Delivered contributes no future excess. We compute these expectations exactly for this fixed toy row, rather than multiply an observed step excess by a horizon.

The theorem and the empirical audit are different statements

With a known true kernel, the calculator can evaluate the true expectations. Without it, sample episodes can estimate them. Zero excess on sampled steps does not establish zero excess almost surely, and a plug-in average is not a certified expectation bound.

Current manuscript audit Deployed p Worst-seed plug-in p + mean stopped excess
Congestion (both roles) 0.10 0.10
Bertrand, Chicken, Markov Stag Hunt 0.20 0.20
Gathering 0.20 0.2002
Pursuit–Evasion 0.16 0.291

Snapshot of figures/tables/dominance_audit.tex at e049b7c: frozen-policy evaluation, 200 episodes per seed, five seeds. These are reported empirical estimates. The paper counts excess below 10⁻¹² as floating-point noise; the toy calculation above uses the mathematical positive part.

What changes about the floor interpretation?

A floor rising past the closest level can break the coverage argument. It does not logically imply a safety failure: the actual law may still satisfy risk dominance. Conversely, the floor heuristic does not prove either condition. The paper’s patience screen delays raises with patience 4096, but retains patience 64 as primary because the larger value does not improve reward consistently across environments.

Use coverage for a prospective safety certificate. Use the dominance audit to investigate whether a learned shield’s committed W was risk-conservative in the evaluated trajectories. The original anytime theorem still allows non-monotone opponent behaviour whenever the actual family remains covered.

Source: omsh-paper/main.tex, cor:risk_dominance, appsec:dominance_audit, and “The monotone floor in practice”; figures/tables/patience_screen.tex. The trained-policy audit covers frozen evaluation, not the changing opponents during training.